实现两个线程交叠输出1-n
#include <bits/stdc++.h> #include <mutex> #include <windows.h> using namespace std; mutex m; //定义互斥信号量 condition_variable cond1, cond2; int cur = 1; //定义当前打印到哪个数字了 void thread1() { while (cur <= 100) { unique_lock<mutex> lock(m); cout << "线程1打印" << cur++ << endl; cond2.notify_one(); //通知等待的线程2 cond1.wait(lock); //线程1进入等待 lock.unlock(); Sleep(1); } } void thread2() { while (cur <= 100) { unique_lock<mutex> lock(m); cout << "线程2打印" << cur++ << endl; cond1.notify_one(); //唤醒线程1 cond2.wait(lock); //线程2进入等待 lock.unlock(); Sleep(1); } } int main() { thread t1(thread1); thread t2(thread2); t1.join(); t2.join(); return 0; }